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Thus, we have u(x,y) = A(x)exy2 (c) Integrating the first PDE and the second PDE gives u = c 1(y)x c 2(y) and u = c 3(x)y c 4(x), respectively Equating these two functions gives u = axy bx cy k Alternatively, uxx = 0 gives u = c 1(y)x c 2(y) Then from uyy = 0, we get uyy = c′′ 1xc′′2 = 0, hence c′′ 1 = 0,c′′2 = 0I j h n _ k k b h g Z e v g u c i Z d _ l,O n e c a n so lv e fo r th e v a ria b le s x an d y in te rm s of a 5 b g c s d ; Pdf Strongly Secure Authenticated Key Exchange In The Standard Model Semantic Scholar ‰Âˆ¤‚¢ ƒC[ƒuƒC ƒtƒŒƒ“ƒY ƒ|ƒPƒbƒgƒ‚ƒ“ƒXƒ^[ ƒCƒ‰ƒXƒg